Answer
$\dfrac{\cos x\sec x}{\cot x}=\tan x$
Work Step by Step
$\dfrac{\cos x\sec x}{\cot x}$
Substitute $\sec x$ with $\dfrac{1}{\cos x}$ and $\cot x$ with $\dfrac{\cos x}{\sin x}$ and simplify:
$\dfrac{\cos x\sec x}{\cot x}=\dfrac{\cos x\Big(\dfrac{1}{\cos x}\Big)}{\dfrac{\cos x}{\sin x}}=\dfrac{1}{\dfrac{\cos x}{\sin x}}=\dfrac{\sin x}{\cos x}=\tan x$
