Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 79

Answer

$-\dfrac{1}{10}$

Work Step by Step

Use the rule $a^{-m}=\left(\dfrac{1}{a}\right)^m$ to obtain: $(-1000)^{-\frac{1}{3}}=\left(\frac{1}{-1000}\right)^{\frac{1}{3}}$ Use $-1000=(-10)^3$. $=\left(\dfrac{1}{(-10)^3}\right)^{\frac{1}{3}}$ Use the rule $\left(\dfrac{a}{b}\right)^n=\dfrac{a^m}{b^m}$: $=\frac{1^{\frac{1}{3}}}{\left((-10)^3\right)^{\frac{1}{3}}}$ $=\frac{1}{\left((-10)^3\right)^{\frac{1}{3}}}$ Use the rule $\left(a^m\right)^n=a^{mn}$, then simplify to obtain: $=\dfrac{1}{(-10)^{3\cdot \frac{1}{3}}}$ $=\dfrac{1}{(-10)^{1}}$ $=-\dfrac{1}{10}$ Hence, the correct answer is $-\frac{1}{10}$.
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