Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 23

Answer

$6\sqrt{x}$

Work Step by Step

Use $36=6^2$. $\sqrt{36x}=\sqrt{6^2x}$ Use $\sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{b}$ to obtain: $=\sqrt{6^2}\sqrt{x}$ Simplify. $=6\sqrt{x}$ Hence, the correct answer is $6\sqrt{x}$.
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