Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 24

Answer

$3x^2\sqrt{x}$

Work Step by Step

Use $9=3^2$. $\sqrt{9x^5}=\sqrt{3^2x^4\cdot x}$ Use properties of radicals. $=\sqrt{3^2x^4}\sqrt{x}$ $=\sqrt{3^2(x^2)^2}\sqrt{x}$ $=\sqrt{(3x^2)^2}\sqrt{x}$ Simplify. $=3x^2\sqrt{x}$ Hence, the correct answer is $3x^2\sqrt{x}$.
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