Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 35

Answer

$\sqrt{2}$

Work Step by Step

Simplify each radical by factoring the radicand such that one of the factors is a perfect square: $-\sqrt{18}+2\sqrt8\\ =-\sqrt{9\cdot 2}+2\sqrt{4\cdot 2}\\ =-\sqrt{3^2\cdot 2}+2\sqrt{2^2\cdot 2}\\$ Use the rule $\sqrt{a\cdot b}=\sqrt{a} \cdot \sqrt{b}$ then simplify: $=-\sqrt{3^2}\cdot \sqrt{2}+2\sqrt{2^2}\cdot \sqrt{2}$ $=-3\cdot \sqrt{2}+2\cdot2\cdot \sqrt{2}$ $=-3\sqrt{2}+4\sqrt{2}$ Factor out $\sqrt{2}$ then simplify. $=\sqrt{2}(-3+4)$ $=\sqrt{2}(1)$ $=\sqrt{2}$ Hence, the correct answer is $\sqrt{2}$.
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