Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 49

Answer

$\dfrac{\sqrt 2}{2}$

Work Step by Step

Rationalize the denominator by multiplying $\sqrt2$ to both the numerator and the denominator: $\dfrac{1}{\sqrt 2}=\dfrac{1}{\sqrt 2} \cdot \dfrac{\sqrt 2}{\sqrt 2}$ Simplify. $=\dfrac{\sqrt 2}{(\sqrt 2)^2}$ $=\dfrac{\sqrt 2}{2}$ Hence, the correct answer is $\frac{\sqrt 2}{2}$.
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