Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 19

Answer

$x^3y^2$.

Work Step by Step

Use $x^{12}=(x^3)^4$ and $y^8=(y^2)^4$. $=\sqrt[4]{(x^3)^4(y^2)^4}$ Separate using the rule $\sqrt[n]{a\cdot b}=\sqrt[n]{a} \cdot \sqrt[n]{b}, a,b>0$ to obtain:. $=\sqrt[4]{(x^3)^4}\sqrt[4]{(y^2)^4}$ Simplify. $=x^3y^2$ Hence, the correct answer is $x^3y^2$.
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