Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 32

Answer

$-30 \sqrt{6}$.

Work Step by Step

Multiply the numerical coeffiients together: $(5\sqrt{8})(-3\sqrt{3})\\ =(-5\cdot 3)\sqrt{8}\cdot \sqrt{3}\\ =-15\sqrt8\cdot\sqrt3$ Use the product rule $\sqrt{a}\cdot \sqrt{b}=\sqrt{ab}, a, b>0$ to obtain: $=-15\sqrt{8 \cdot 3}\\ =-15\sqrt{24}$ Factor the radicand so that on factor is a perfect square number. $=-15\sqrt{4 \cdot 6}$ $=-15\sqrt{2^2 \cdot 6}$ Use the product rule. $=-15\sqrt{2^2} \cdot \sqrt{6}$ $=-15\cdot 2 \cdot \sqrt{6}$ $=-30 \sqrt{6}$ Hence, the correct answer is $-30 \sqrt{6}$.
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