Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 74

Answer

$\dfrac{1}{64}$

Work Step by Step

Since $16=4^2$, the given expression is equivalent to: $16^{-\frac{3}{2}}=(4^2)^{-\frac{3}{2}}$ Use the rule $\left(a^m\right)^n=a^{mn}$, then simplify to obtain: $=4^{2\cdot\frac{-3}{2}}$ $=4^{-3}$ Use the rule $a^{-m}=\dfrac{1}{a^m}$, then simplify to obtain:. $=\dfrac{1}{4^{3}}$ $=\dfrac{1}{64}$ Hence, the correct answer is $\frac{1}{64}$.
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