Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 20

Answer

$x^2y$

Work Step by Step

Use $x^{10}=(x^2)^5$. $\sqrt[5]{x^{10}y^{5}}=\sqrt[5]{(x^2)^5(y^5)}$ Separate using the rule $\sqrt[n]{a\cdot b}=\sqrt[n]{a} \cdot \sqrt[n]{b}, a,b>0$ to obtain: $=\sqrt[5]{(x^2)^5}\sqrt[5]{y^5}$ Simplify. $=x^2y$ Hence, the correct answer is $x^2y$.
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