Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 28

Answer

$10x^2$

Work Step by Step

Use the rule $\sqrt[n]{a} \cdot \sqrt[n]{b}=\sqrt[n]{a\cdot b}$ to obtain: $\sqrt{5x}\sqrt{20x^3}=\sqrt{5x\cdot 20x^3}$ Simplify. $=\sqrt{100x^4}$ Use $100=10^2$ and $x^4=(x^2)^2$. $=\sqrt{10^2(x^2)^2}$ Simplify using $\sqrt{a^2}=a, a>0$ to obtain:. $=10x^2$ Hence, the correct answer is $10x^2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.