Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 29

Answer

$15 \sqrt[3]{3}$

Work Step by Step

Use $9=3^2$ to obtain: $(\sqrt{5}\sqrt[3]{9})^2=(\sqrt{5}\sqrt[3]{3^2})^2$ Use the rule $\sqrt[n]{a^m}=a^{\frac{m}{n}}$ to obtain: $=\left(5^{\frac{1}{2}}3^{\frac{2}{3}}\right)^2$ Use the Power Rule $\left(a^m\right)^n=a^{mn}$ to obtain: $=5^{\frac{1}{2}\cdot 2}3^{\frac{2}{3}\cdot 2}$ $=5^{1}3^{\frac{4}{3}}$ Simplify. $=5\cdot3^{\frac{3+1}{3}}$ $=5\cdot3^{1+\frac{1}{3}}$ $=5\cdot3\cdot 3^{\frac{1}{3}}$ $=15\cdot 3^{\frac{1}{3}}$ $=15\cdot \sqrt[3]{3}$ Hence, the correct answer is $15 \sqrt[3]{3}$.
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