Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 50

Answer

$\dfrac{2\sqrt 3}{3}$

Work Step by Step

Rationalize the denominator by multiplying $\sqrt3$ to both the numerator and the denominator: $\dfrac{2}{\sqrt 3} =\dfrac{2}{\sqrt 3} \cdot \dfrac{\sqrt 3}{\sqrt 3}$ Simplify. $=\dfrac{2\sqrt 3}{(\sqrt 3)^2}$ $=\dfrac{2\sqrt 3}{3}$ Hence, the correct answer is $\frac{2\sqrt 3}{3}$.
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