Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 11

Answer

$3$.

Work Step by Step

Use $27=3^3$. $\sqrt[3]{27}=\sqrt[3]{3^3}=3$ Hence, the correct answer is $3$.
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