Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 63

Answer

$\left\{\dfrac{9}{2}\right\}$

Work Step by Step

Raise each side to the power $3$. $\left(\sqrt[3]{2t-1}\right)^3=2^3$ $2t-1=8$ Add $1$ to both sides. $\begin{align*} 2t-1+1&=8+1\\ 2t&=9\end{align*}$ Divide both sides by $2$. $\begin{align*} \dfrac{2t}{2}&=\dfrac{9}{2}\\ t&=\dfrac{9}{2} \end{align*}$ Hence, the solution set is $\left\{\frac{9}{2}\right\}$.
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