Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.10 nth Roots; Rational Exponents - A.10 Assess Your Understanding - Page A88: 37

Answer

$2\sqrt 3$

Work Step by Step

Multiply using the FOIL (first, outer, inner, last) method: $(\sqrt 3+3)(\sqrt 3-1)=\sqrt 3 \cdot \sqrt 3-1\cdot \sqrt 3+3\cdot \sqrt 3- 3\cdot 1$ Simplify. $=(\sqrt 3)^2-\sqrt 3+3 \sqrt 3- 3$ $=3-\sqrt 3+3 \sqrt 3- 3$ $=-\sqrt 3+3 \sqrt 3$ Factor out $\sqrt{3}$ then simplify. $=\sqrt 3(-1+3) $ $=\sqrt 3(2) $ $=2\sqrt 3 $ Hence, the correct answer is $2\sqrt 3$.
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