Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 128

Answer

$6(x + 5)^3(x - 1)(x+1)$

Work Step by Step

We factor out $(x + 5)^3(x - 1)$ and distribute, combine like terms, and simplify as follows: \begin{align*} 4(x + 5)^3(x - 1)^2 &+ (x + 5)^4 \cdot2(x - 1)\\ &=(x + 5)^3(x - 1)[4(x-1)+2(x+5)]\\ &=(x + 5)^3(x - 1)[4x-4+2x+10]\\ &=(x + 5)^3(x - 1)(6x+6)\\ &=6(x + 5)^3(x - 1)(x+1). \end{align*}
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