Answer
$(x-1)(x-16)$
Work Step by Step
To factor a second-degree polynomial $x^2 - 17x + 16$, we have to find integers whose product is $16$ and whose sum is $-17$. That is, we have $-1$ and $-16$ where $-1-16=-17$ and $-1\times (-16)=16$. Thus:
$$
x^2 - 10x + 16=(x-1)(x-16)
.$$
