Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 46

Answer

$(x-1)(x-16)$

Work Step by Step

To factor a second-degree polynomial $x^2 - 17x + 16$, we have to find integers whose product is $16$ and whose sum is $-17$. That is, we have $-1$ and $-16$ where $-1-16=-17$ and $-1\times (-16)=16$. Thus: $$ x^2 - 10x + 16=(x-1)(x-16) .$$
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