Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 59

Answer

$(z+1)(2z+3)$

Work Step by Step

First, we write $$ 2z^2 + 5z + 3=2z^2 + 2z+3z + 3 .$$ By grouping the first two terms and the second two terms and then taking common factors, we have $$ 2z^2 + 2z+3z + 3=2z(z+1)+3(z+1)=(z+1)(2z+3) .$$
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