Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 75



Work Step by Step

The polynomial $x^2-36$ is a difference of the two squares $x^2$ and $6^2$. That is, by using the fact that $a^2-b^2=(a-b)(a+b)$, we have $$ x^2-36=x^2-6^2=(x-6)(x+6) .$$
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