Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 89

Answer

$$3(x+2)(x-6)$$

Work Step by Step

We take out the constant $3$ from the given polynomial: $$3x^2 - 12x - 36=3(x^2 - 4x - 12)$$ To factor the remaining polynomial, we have to find integers whose product is $-4$ and whose sum is $-6$. That is, we have $2$ and $-6$ where $2-6=-4$ and $2\times (-6)=-12$. Thus $$ 3(x^2 - 4x - 12)=3(x+2)(x-6) .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.