Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 105

Answer

$$-(4x+1)(4x-5) .$$

Work Step by Step

First, for the polynomial $5 + 16x - 16x^2$, we write $$5 + 16x - 16x^2=-(16x^2-16x-5)=-(16x^2+4x-20x-5) .$$ By grouping the first two terms and the second two terms and then taking out common factors, we have $$-(16x^2+4x-20x-5) =-(4x(4x+1)-5(4x+1))\\ =-(4x+1)(4x-5) .$$
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