Work Step by Step
We have $6x^2 + 8x + 2=2(3x^2+4x+1)=2(3x^2+3x+x+1)$ By grouping the first two terms and the second two terms, and then taking common factors, we have $$ 2(3x^2+3x+x+1)=2(3x(x+1)+(x+1))=2(x+1)(3x+1) .$$
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