Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 47



Work Step by Step

To factor a second-degree polynomial $x^2 -7x - 8$, we have to find integers whose product is $-8$ and whose sum is $-7$. That is, we have $1$ and $-8$ where $1-8=-7$ and $1\times (-8)=-8$. Thus: $$ x^2 - 7x - 8=(x+1)(x-8) .$$
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