Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 60



Work Step by Step

First, for the polynomial $6z^2 + 5z + 1$, we write $$ 6z^2 + 5z + 1=6z^2 + 2z+3z + 1 .$$ By grouping the first two terms and the second two terms and then taking common factors, we have $$ 6z^2 + 2z+3z + 1=2z(3z+1)+(3z+1)=(3z+1)(2z+1) .$$
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