Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 42

Answer

$(x+1)(x+8)$

Work Step by Step

To factor a second-degree polynomial $x^2 + 9x + 8$, we have to find integers whose product is $8$ and whose sum is $9$. That is, we have $1$ and $8$ where $1+8=9$ and $1\times 8=8$. Thus: $$ x^2 + 9x + 8=(x+1)(x+8) .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.