# Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 31

$$(4x+1)^2 .$$

#### Work Step by Step

The polynomial $16x^2+8x+1$ is a complete square since it is of the form $a^2+2ab+b^2=(a+b)^2$. Thus, by putting $a=4x$, $b=1$, we have $$16x^2+8x+1=(4x+1)^2 .$$

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