Answer
$$(4x+1)^2 .$$
Work Step by Step
The polynomial $16x^2+8x+1$ is a complete square since it is of the form $a^2+2ab+b^2=(a+b)^2$. Thus, by putting $a=4x$, $b=1$, we have
$$ 16x^2+8x+1=(4x+1)^2 .$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 31
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