Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 35


$(x +3)(x^2 -3x +9)$

Work Step by Step

Since $x^3+27$ is a sum of the two cubes $x^3$ and $3^3$, then by making use of the sum of two cubes $$a^3 + b^3 = (a + b)(a^2 - ab + b^2),$$ we have \begin{align*} x^3 +27&=x^3+3^3\\ &= (x +3)(x^2 -3x + 3^2)\\ &= (x +3)(x^2 -3x +9) \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.