Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 126

Answer

$ x^2(32x-9)$

Work Step by Step

We factor out $x^3$ and distribute, combine like terms, and simplify as follows: \begin{align*} 3x^2(8x - 3) + x^3 \cdot 8&= x^2[3(8x-3)+8x]\\ &= x^2[24x-9+8x]\\ &= x^2(32x-9). \end{align*}
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