Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 96

Answer

$2(x+1)(4x-1)$

Work Step by Step

We have $ 8x^2 + 6x - 2=2(4x^2+3x-1)=2(4x^2+4x-x-1)$. By grouping the first two terms and the second two terms, and then taking common factors, we have $$ 2(4x^2+4x-x-1)=2(4x(x+1)-(x+1))=2(x+1)(4x-1) .$$
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