Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 106


$$-(x-1)(16x+5) .$$

Work Step by Step

First, for the polynomial $5 + 11x - 16x^2$, we write $$5 + 11x - 16x^2=-(16x^2-11x-5)=-(16x^2-16x+5x-5) .$$ By grouping the first two terms and the second two terms and then taking common factors, we have $$-(16x^2-16x+5x-5)=-(16x(x-1)+5(x-1))\\ =-(x-1)(16x+5) .$$
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