Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 74


$\frac{1}{36}$, $(x+(1/6))^2$

Work Step by Step

To complete the square of $x^2 +\frac{1}{3}x$, we add $(b/2)^2$. In this case, the "$b$" is the second coefficient, $1/3$, so we add $((1/3)/2)^2=1/36$ and we have $x^2 +\frac{1}{3}x+\frac{1}{36}$. Then by factorization, we get $$ x^2 +\frac{1}{3}x+\frac{1}{36}=(x+(1/6))^2 .$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.