Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 19

Answer

$(x-4)(x+4)$

Work Step by Step

By using the difference of two squares $x^2-a^2=(x-a)(x+a)$, we have $$ x^2 - 16=(x-4)(x+4) .$$
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