## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 63

#### Answer

$(x-2)(3x+4)$

#### Work Step by Step

First, for the polynomial $3x^2 - 2x - 8$, we write $$3x^2 - 2x - 8=3x^2 - 6x +4x- 8 .$$ By grouping the first two terms and the second two terms and then taking common factors, we have $$3x^2 - 6x +4x- 8=3x(x-2)+4(x-2)=(x-2)(3x+4) .$$

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