Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 69


$25$, $(x+5)^2$

Work Step by Step

To complete the square of $x^2 + 10x$, we add $(b/2)^2$. In this case, the "$b$" is the second coefficient, $10$. Thus, we add $(10/2)^2=25$, that is, we have $x^2 + 10x+25$. Then by factorization, we get $$ x^2 + 10x+25=(x+5)^2 .$$
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