Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A40: 127

Answer

$5(x + 3)(x - 2)^2(x+1)$

Work Step by Step

We factor out $(x + 3)(x - 2)^2$ and distribute, combine like terms, and simplify as follows: \begin{align*} 2(x + 3)(x - 2)^3 &+ (x + 3)^2 \cdot 3(x - 2)^2\\ &=(x + 3)(x - 2)^2[2(x-2)+3(x+3)]\\ &=(x + 3)(x - 2)^2[2x-4+3x+9]\\ &=(x + 3)(x - 2)^2(5x+5)\\ &=5(x + 3)(x - 2)^2(x+1) \end{align*}
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