Answer
$(x+2)(x+4)$
Work Step by Step
To factor a second-degree polynomial $x^2 + 6x + 8$, we have to find integers whose product is $8$ and whose sum is $6$. That is, we have $2$ and $4$ where $2+4=6$ and $2\times 4=8$. Thus:
$$
x^2 + 6x + 8=(x+2)(x+4)
.$$
