## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$3(4x-3)(4x-1)$
We factor out $(4x - 3)$ and distribute, combine like terms, and simplify as follows: \begin{align*} (4x - 3)^2 &+ x \cdot 2(4x - 3)\cdot 4\\ &=(4x - 3)[4x-3+8x)]\\ &=(4x-3)(12x-3)\\ &=3(4x-3)(4x-1). \end{align*}