Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.4 Factoring Polynomials - A.4 Assess Your Understanding - Page A41: 131

Answer

$6(3x - 5) (2x + 1)^2(5x-4)$

Work Step by Step

We factor out $6(3x - 5) (2x + 1)^2$ and combine like terms as follows: \begin{align*} 2(3x - 5) \cdot 3(2x + 1)^3& + (3x - 5)^2 \cdot 3(2x + 1)^2 \cdot 2\\ &=6(3x - 5) (2x + 1)^2[2x+1+3x-5]\\ &=6(3x - 5) (2x + 1)^2(5x-4). \end{align*}
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