#### Answer

$k=\pm 18$

#### Work Step by Step

In order for the equation to have one solution, the discriminant must be 0. So we have:
$36^{2}-4(k)(k)=0$
$4k^{2}=36^{2}$
$2k=\pm 36$
$k=\pm36/2=\pm 18$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$k=\pm 18$

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