Answer
$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$
Work Step by Step
We solve by factoring:
$4x^{2}+16x-9=0$
$(2x-1)(2x+9)=0$
$2x-1=0$ or $2x+9=0$
$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 39
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