College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises: 39

Answer

$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$

Work Step by Step

We solve by factoring: $4x^{2}+16x-9=0$ $(2x-1)(2x+9)=0$ $2x-1=0$ or $2x+9=0$ $x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$
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