#### Answer

$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$

#### Work Step by Step

We solve by factoring:
$4x^{2}+16x-9=0$
$(2x-1)(2x+9)=0$
$2x-1=0$ or $2x+9=0$
$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=\displaystyle \frac{1}{2}$ or $x=-\displaystyle \frac{9}{2}$

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