Answer
$x=-3\pm\sqrt{11}$
Work Step by Step
We complete the square:
$x^{2}+6x-2=0$
$x^{2}+6x=2$
$x^{2}+6x+9=2+9$
$(x+3)^{2}=11$
$x+3=\pm\sqrt{11}$
$x=-3\pm\sqrt{11}$
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