College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 18

Answer

$x=-3\pm\sqrt{11}$

Work Step by Step

We complete the square: $x^{2}+6x-2=0$ $x^{2}+6x=2$ $x^{2}+6x+9=2+9$ $(x+3)^{2}=11$ $x+3=\pm\sqrt{11}$ $x=-3\pm\sqrt{11}$
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