College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 24


$x=-1$ or $x=19$

Work Step by Step

We complete the square: $x^{2}-18x=19$ $x^{2}-18x+(-9)^{2}=19+(-9)^{2}=19+81=100$ $(x-9)^{2}=100$ $x-9=\pm\sqrt{100}=\pm 10$ $x=9\pm 10$ So we have: $x=-1$ or $x=19$
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