#### Answer

$x=3$ or $x=5$

#### Work Step by Step

We solve by factoring:
$x^{2}-8x+15=0$
$(x-3)(x-5)=0$
$x-3=0$ or $x-5=0$
So we have: $x=3$ or $x=5$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=3$ or $x=5$

We solve by factoring:
$x^{2}-8x+15=0$
$(x-3)(x-5)=0$
$x-3=0$ or $x-5=0$
So we have: $x=3$ or $x=5$

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