## College Algebra 7th Edition

$w^{2}=3(w-1)=3w-3$ $w^{2}-3w+3=0$ We solve using the quadratic formula: $w=\frac{-(-3)\pm\sqrt{(-3)^{2}-4(1)(3)}}{2(1)}=\frac{3\pm\sqrt{9-12}}{2}=\frac{3\pm\sqrt{-3}}{2}$ We can't take the square root of a negative, so there are no (real) solutions.