College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 41

Answer

No solution.

Work Step by Step

$w^{2}=3(w-1)=3w-3$ $w^{2}-3w+3=0$ We solve using the quadratic formula: $w=\frac{-(-3)\pm\sqrt{(-3)^{2}-4(1)(3)}}{2(1)}=\frac{3\pm\sqrt{9-12}}{2}=\frac{3\pm\sqrt{-3}}{2}$ We can't take the square root of a negative, so there are no (real) solutions.
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