#### Answer

No solution.

#### Work Step by Step

$w^{2}=3(w-1)=3w-3$
$w^{2}-3w+3=0$
We solve using the quadratic formula:
$w=\frac{-(-3)\pm\sqrt{(-3)^{2}-4(1)(3)}}{2(1)}=\frac{3\pm\sqrt{9-12}}{2}=\frac{3\pm\sqrt{-3}}{2}$
We can't take the square root of a negative, so there are no (real) solutions.