#### Answer

No solution.

#### Work Step by Step

We use the quadratic formula:
$x^{2}-2.450x+1.501=0$
$x=\displaystyle \frac{-(-2.45)\pm\sqrt{(-2.45)^{2}-4(1)(1.501)}}{2(1)}=\frac{2.45\pm\sqrt{6.0025-6.004}}{2}=\frac{2.45\pm\sqrt{-0.0015}}{2}$
We can't take the square root of a negative, so there are no (real) solutions.