College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 16


$x=-\displaystyle \frac{3}{2}$ or $x=\displaystyle \frac{7}{3}$

Work Step by Step

We solve by factoring: $6x(x-1)=21-x$ $6x^{2}-6x=21-x$ $6x^{2}-5x-21=0$ $(2x+3)(3x-7)=0$ $2x+3=0$ or $3x-7=0$ So we have: $x=-\displaystyle \frac{3}{2}$ or $x=\displaystyle \frac{7}{3}$
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