College Algebra 7th Edition

$x=-3/2$ or $x=1/2$
We complete the square: $x^{2}+x-\displaystyle \frac{3}{4}=0$ $x^{2}+x=\frac{3}{4}$ $x^{2}+x+\frac{1}{4}=\frac{3}{4}+\frac{1}{4}=1$ $(x+\frac{1}{2})^{2}=1$ $x+\frac{1}{2}=\pm 1$ $x=-\frac{1}{2}\pm 1$ So the two solutions are: $x=-\displaystyle \frac{1}{2}-1=-\frac{3}{2}$ And: $x=-\displaystyle \frac{1}{2}+1=\frac{1}{2}$