#### Answer

$x=1$ or $x=-\frac{3}{2}$

#### Work Step by Step

We solve by factoring:
$2x^{2}+x-3=0$
$(x-1)(2x+3)=0$
$x-1=0$ or $2x+3=0$
$x=1$ or $x=-\frac{3}{2}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=1$ or $x=-\frac{3}{2}$

We solve by factoring:
$2x^{2}+x-3=0$
$(x-1)(2x+3)=0$
$x-1=0$ or $2x+3=0$
$x=1$ or $x=-\frac{3}{2}$

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