Answer
$x=1$ or $x=-\frac{3}{2}$
Work Step by Step
We solve by factoring:
$2x^{2}+x-3=0$
$(x-1)(2x+3)=0$
$x-1=0$ or $2x+3=0$
$x=1$ or $x=-\frac{3}{2}$
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