Answer
$x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$
Work Step by Step
We solve by factoring:
$6x^{2}-x-12=0$
$(3x+4)(2x-3)=0$
$3x+4=0$ or $2x-3=0$
So we have: $x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 10
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