Answer
$x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$
Work Step by Step
We solve by factoring:
$6x^{2}-x-12=0$
$(3x+4)(2x-3)=0$
$3x+4=0$ or $2x-3=0$
So we have: $x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$