College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 10


$x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$

Work Step by Step

We solve by factoring: $6x^{2}-x-12=0$ $(3x+4)(2x-3)=0$ $3x+4=0$ or $2x-3=0$ So we have: $x=-\displaystyle \frac{4}{3}$ or $x=\displaystyle \frac{3}{2}$
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